Find the 7th term of the geometric sequence with the given terms.
a4 = -8 and a5 = -40; a7 = _______. When I solved this I got -104 but it said it was wrong.

Question

Find the 7th term of the geometric sequence with the given terms. 
a4 = -8 and a5 = -40; a7 = _______. When I solved this I got -104 but it said it was wrong.

anonymous · Answer

$$=-200r=\frac{ a5 }{a4 }=\frac{ -40 }{ -8 }=5$$
a6=a5*5=-40*5=-200
a7=a6*r=-200*5=-1000

anonymous · Answer

$$an=a1r ^{n-1}$$
$$a4=a1r ^{4-1}=a1r ^{3}=-8$$
$$a5=a1r ^{5-1}=a1r ^{4}=-40$$
$$\frac{ a1r^4 }{a1r^3 }=\frac{ -40 }{-8 },r=5,$$
$$a7=a1r ^{7-1}=a1r^6=a1r^4r^2=-40\left( 5 \right)^2=-40*25=-1000$$

anonymous · Answer

Ok Ok that makes more sense. I have no idea how I got -104. Thank you for your time!:)