Question

Please help :( solve the following equation with rational exponents and radicals

(x-2)^2/3=49

Answer 1

this website helps u a lot

Answer 2

http://www.tiger-algebra.com/drill/%28x-2%29~2/3=49/

Answer 3

is that \[\frac{ (x-2)^2 }{ 3 } = 49\] ?

Answer 4

no its( x-2) raised to the 2 thirds power equals 49

Answer 5

\[(x-2)^{2/3}=49\]
multiply both sides by the inverse of 2/3 to cancel out the exponent on the left side.
\[((x-2)^{2/3})^{3/2} = 49^{3/2}\]
Then you'll have x-2 = 49^(3/2)

Answer 6

k thanks