Question

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if the position of a particle on the x axis at time t is -5t^2, then the average velocity of the particle for 0 12 years ago

Answer 1

x=-5t^2... for t=0, x=0 and for t=3, x=-45

\[v _{avg}=\frac{ \Delta x }{ \Delta t }\]

then\[v _{avg}=-15\]