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Physics 12 Online
OpenStudy (anonymous):

so theres this physics question

OpenStudy (anonymous):

OpenStudy (roadjester):

\(E_A=E_B\) so \(\dfrac 1 2mv_A^2+mgh_A=\dfrac 1 2mv_B^2+mgh_B\)

OpenStudy (anonymous):

The mechanical energy is the sum of the kinetic energy and the potential energy. In the absence of losses due to friction, etc., the mechanical energy at A, B and C will be identical.

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