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find the equation, in standard form of the line passing through the points (2,-3) (4,2)
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Do you know the formula for slope? and then the point-slope for of an equation of a line?
point-slope form, not for
isn't the slope form m=y1-y2/x2-x1?
first, solve for the slope then use that slope and one of the points into point-slope form solve for y then simplify into standard form
yup! thats to find the slope. then you plug that answer into : y-y1=m(x-x1) you can use either point for the second equation
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and sorry, your slope one should be m=y2-y1/x2-x1
what would you do with the y--3?
the negatives cancel eachother out, making it positive
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