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Trigonometry
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HELP ME CHECK MY WORK y=4cos(x+(pi/3))-2 a. Amplitude- 4 b. period- 2pi c. phase shift- pi/3 to the left d. vertical translation- down two
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good job
is it all right @sourwing
yea
I do think though, the phase shift is negative, is all
\(\bf y=Acos(Bx-C)\qquad \textit{phase shift}=\cfrac{C}{B} \\ \quad \\ y=4cos\left(x+\frac{\pi}{3}\right)\implies y=4cos\left(x-\left[-\frac{\pi}{3}\right]\right)\) other than that, is correct :)
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