Question

A gym offers regular memberships for $80 per month and off-peak memberships for $60 per month. Last month, the gym sold a total of 420 memberships for a total of $31,100. How many memberships sold were regular memberships?

A.)125

B.) 140

C.) 235

D.) 295

Answer 1

let \(r\) be the number of regular memberships. If they sold 420 memberships, then \(420-r\) is the number of off-peak memberships.

Revenue from regular memberships at $80 each is \(80r\)
Revenue from off-peak memberships at $60 each is \(60(420-r)\)

Total revenue is regular + off-peak = $31,100
\[31,100 = 80r + 60(420-r)\]
Solve for \(r\) and you've got your regular membership count.

Answer 2

So is it A

Answer 3

That is what i got

Answer 4

If 125 regular memberships were sold, how many off-peak memberships were sold?

Answer 5

295

Answer 6

So is the answer D

Answer 7

Stop guessing. You can work the problem out from what I gave you, and KNOW that you have the right answer.

Here's how to check your answer. Suppose you think the answer is A, 125 regular memberships (which implies 295 off-peak memberships).

125 * 80 + 295*60 = 10000 + 17700 = 27700
27700 does not equal 31100, so A is not the correct answer.

Answer 8

Can you show me your work that led you to think A was the correct answer? If you honestly did the problem and concluded that A was the correct answer, you must have made a mistake somewhere, and we should find the mistake and correct it so that you don't make similar mistakes in the future.