Question

please help :(

Answer 1

well i have a few questions i need help with,but well don one at a time

Answer 2

solve the following system of quadratic and linear equations y=-x^2+4x-3 and x+y=1

Answer 3

How to Solve using Algebra a system of equations
Make both equations into "y =" format
Set them equal to each other
Simplify into "= 0" format (like a standard Quadratic Equation)
Solve the Quadratic Equation!
Use the linear equation to calculate matching "y" values, so we get (x,y) points as answers
An example will help:

Example: Solve these two equations:
y = x2 - 5x + 7
y = 2x + 1

Make both equations into "y=" format:
They are both in "y=" format, so go straight to next step

Set them equal to each other
x2 - 5x + 7 = 2x + 1

Simplify into "= 0" format (like a standard Quadratic Equation)
Subtract 2x from both sides: x2 - 7x + 7 = 1
Subtract 1 from both sides: x2 - 7x + 6 = 0

Solve the Quadratic Equation!
(The hardest part for me)
You can read how to solve Quadratic Equations, but here we will factor the Quadratic Equation:
Start with: x2 - 7x + 6 = 0
Rewrite -7x as -x-6x: x2 - x - 6x + 6 = 0
Then: x(x-1) - 6(x-1) = 0
Then: (x-1)(x-6) = 0

Which gives us the solutions x=1 and x=6

Answer 4

so set your equations rearrange the second equation to y=
x+y=1
y= 1-x
Now set-up the equation
-x^2+4x-3 = 1-x Can you do this step like the example above?

Answer 5

ok well could you maybe help through my probelm

Answer 6

yup that's what Im doing :) Try the step I posted on your own, if u think u got it post, if you don't get it, post anyways it's good learning experience :D

Answer 7

k hang on

Answer 8

@cheergurl_99 ??

Answer 9

Sorry I couldn't help you..

Answer 10

@cheergurl_99 and @nanalew : nanalew's suggestion,

Make both equations into "y=" format:
They are both in "y=" format, so go straight to next step

Set them equal to each other
x2 - 5x + 7 = 2x + 1

is just fine. Since there are three terms on the left and just two on the right, please move the 2 terms on the right to the left. @cheergurl_99?

Answer 11

ok thanks

Answer 12

Hope you'll continue working on this problem.

Answer 13

can you help me with my next question then?

Answer 14

Do you get how to solve the first equation?

Answer 15

@cheergurl_99: I'd much prefer that you finish the present question before moving on to the next one.

Answer 16

okay sure