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7. Determine three consecutive odd integers if the square of the largest integer is 33 less than the sum of the squares of the two smaller integers.
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x=first odd integer x+2 = next odd integer x+4 = third odd integer (x+4)^2=x^2+(x+2)^2-33
thanks! thats exactly what i needed to get me started
after factoring i've got x=9 and x=-5, what am i supposed to do next?
wich x do i use for (x+4), x and (x+2)
*which
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You have two sets of answers: 9, 11, 13 and -5, -3, -1
yes i got that answer now
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