HALP IN GEOMETRY PLSSS♡
(will give medal, pic below)

Question

HALP IN GEOMETRY PLSSS♡
(will give medal, pic below)

anonymous · Answer

attachment

ganeshie8 · Answer

use below :-

exterior angle  =  [ (far arc) - (near arc) ] / 2

beccaboo333 · Answer

Awe my hunnybear can help you ^_^ he's very good in math.

ganeshie8 · Answer

becca :) u need to look at the circle from external point  Y

anonymous · Answer

84-35=49
49/2= 24-5?

ganeshie8 · Answer

not exactly...

ganeshie8 · Answer

$\large \angle Y = \frac{VW -  XZ}{2}$

$\large 35  = \frac{84-  XZ}{2}$

solve XZ

ganeshie8 · Answer

let me knw if smthng doesnt make sense...

anonymous · Answer

so isnt that 84-35/2?

ganeshie8 · Answer

nope, cuz 35 is itself the "external angle", its not the "near arc"

ganeshie8 · Answer

ur goal is to find "near arc XZ"

ganeshie8 · Answer

so u need to solve above equation

ganeshie8 · Answer

$\large \angle Y = \frac{VW -  XZ}{2}$

$\large 35  = \frac{84-  XZ}{2}$

multiply 2 both sides

$\large   70 =  84 - XZ$

subtract 84 both sides

$\large   -14 =   -XZ$

multiply -1 both sides

$\large   14 = XZ$

which is same as :

$\large  XZ = 14$

anonymous · Answer

35?

ganeshie8 · Answer

35 is the external angle GIVEN.

ganeshie8 · Answer

question is about finding XZ

ganeshie8 · Answer

look at diagram bit long.. u will see 35 at the external angle Y

anonymous · Answer

I figured it out, thanks for your heeelp c:

ganeshie8 · Answer

np... u wlc :)