Question

findd2y/dx2 in terms of 3x^2-2y^2=5

Answer 1

Implicit differentiation twice.
1st:
6x - 4yy' = 0
6x = 4yy'
y' = 3x/2y

y'' = ((2y(3)-(3x(2y'))/4y^2
y'' = (6y-6xy')/4y^2
y'' = 3(y - x (3x/2y) )/2y^2
y'' = 3(2y^2 - -3x^2)/2y^3