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cos(arcsin(5/13))
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|dw:1394263791874:dw| Consider this trianlge having angle x there. Therefore, arcsin5/13 = x
|dw:1394263897597:dw| Using pythagoren theorem we can solve for a. And a = 13^2 - 5^2 = 144 = 12 Hence cosx = 12/13 --> it also implies that cos(arcsin5/13) = 12/13 as well.
also, a = sqrt(13^2-5^2) = sqrt(144) = 12
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