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OpenStudy (anonymous):
What value is a discontinuity of x^2+5x+2/x^2+2x-35 ? a. x = -5 b. x = -7 c. x = -2 d. x = -1
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OpenStudy (anonymous):
wherever \(x^2+2x-35=0\)
OpenStudy (anonymous):
since this one factors as \((x+7)(x-5)=0\) the zeros are easy to find
OpenStudy (anonymous):
you good from there?
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