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how can i find the angle measures of trapezoid ABCD inscribed in a circle, only trying to find m
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Hint: in a cyclic quadrilateral opposite angles add up to 180 degrees
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so if m <a = 60 what is m < C?
i am not sure but i know that m<D is 60 as well
and since AD and BC are parallel then < A and <B add up to 180 also
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so then i need to subtract 180-60, right?
yes
i get 120
thats correct <C = 120 also <B = 180 - 60 = 120
ohhhhhh thank you so much lol
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