Question

tan (pi/4+pi/6)=?

Answer 1

\(\bf tan(\alpha+\beta)=\cfrac{tan(\alpha)+tan(\beta)}{1-tan(\alpha)tan(\beta)}\)

those two are well known angles, check your Unit Circle for their values, plug them in :)
keep in mind that \(\bf tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\)