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Using Law of Sines. a=3 b=7 A=70 I am trying to find the SinB using sin-1(7sin70)/3) but I get domain error.
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hmmm can you post a quick screenshot of the material? \(\bf \left[\cfrac{7sin(70^o)}{3}\right]\approx 2.19\qquad recall \implies -1\le sin(\theta)\le 1\)
|dw:1394323071585:dw|
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