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OpenStudy (anonymous):
I need to solve y=2^x using logarithmic differentiation.
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OpenStudy (shamil98):
\[(a^x)' = a^x(\ln~a)\]
OpenStudy (shamil98):
Would it not be just: \[y' = 2^x(\ln 2)\] ?
OpenStudy (anonymous):
I got the answer using that method but need this method. I would take log of both sides but I get stuck
OpenStudy (anonymous):
heres where I lock up |dw:1394333433739:dw|
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