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Mathematics 10 Online
OpenStudy (anonymous):

Please help me to solve this. If cot[θ] = -2, find the value of: cot[θ] + cot[θ - Pi] + cot(θ - 2 Pi)

OpenStudy (dumbcow):

|dw:1394347529248:dw| so subtracting 2pi gets you to same spot, cot(A-2pi) = -2 subtracting pi gets you to same reference angle in opposite quadrant, for tangent opposite(diagonal) quadrants are equal, cot(A-pi) = -2

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