Question

A batch code on the side of a food container is composed of seven dots, two blue, two white and three black.
if five dots chosen from the seven dots. Find the number of different possible codes in this case.

Answer 1

please help

Answer 2

many possibles cases here, they are
(2Blue,2White,1black), (2Blue,3white),(2white,3black),(1blue,2white,2black),(2blue,1white,2black). so, it has 5 combinations. and each combination has different possible codes.

for case of (2Blue,2White,1black) :
2C2 * 2C2 * 3C1 = 3 ways

just continue for other cases, try it

Answer 3

got it ?

Answer 4

trying please wait

Answer 5

is that correct
(2c2*2c2*3c1)+(2c2*3c3)*2+(2c1*2c2*3c2)*2

Answer 6

it is not correct

Answer 7

the answer is 130

Answer 8

i agree with your first anwes, it is (2c2*2c2*3c1)+(2c2*3c3)*2+(2c1*2c2*3c2)*2
3 + 1*2 + 6*2 = 17 ways

Answer 9

but the answer in in the text book is 130

Answer 10

i dont know why it is be 130, maybe i make mistake. sorry :)

Answer 11

never mind