Question

Please someone tell me what I did wrong, or if I have something left Factoring

Answer 1

\[36v^3-12v^2+48v-168\]
\[12(3v^3-v^2+4v-14)\]

Answer 2

Is 12 the GCF ?

Answer 3

you are correct so far - taking out THE GCF 12

Answer 4

So then it would be
\[(12) v^2(3v-1)+2(2v-7)\]

Answer 5

12[ v^2(3v - 1) + 2(2v - 7)]

Answer 6

the 12 multiplies all that's in the square brackets

Answer 7

I cant see any way to factor the cubic polynomial ..

Answer 8

what I mean is there is no factors of the form (x + a)(x + b)( x + c) where a,b and c are integers

Answer 9

So it is not factorable?

Answer 10

@cwrw238