Question

Geo help

Answer 1

x=4

Answer 2

do you need to clarify?

Answer 3

Use the Pythagorean theorem:

\[x^2+(x-2)^2 = 20\]
\[2x^2-4x+4=20\]
\[x^2-2x-8=0\]
x = 4 or -2, but since it's a side length, it must be 4.

Answer 4

use the pythagorean theorem \(\bf {\color{blue}{ c^2=a^2+b^2}}
\\ \quad \\ \quad \\
(\sqrt{20})^2=(x-2)^2+(x)^2\implies 20=(x-2)(x-2)x^2\)

Answer 5

woops I lost my + =) hehe \(\bf {\color{blue}{ c^2=a^2+b^2}}
\\ \quad \\ \quad \\
(\sqrt{20})^2=(x-2)^2+(x)^2\implies 20=(x-2)(x-2)+x^2\)