Question

Please help, & Explain !
x^2+8x+16=16

Answer 1

ok first you should get rid of the 16

Answer 2

\[x ^{2}+8x+16=16\]

Answer 3

ok, so to get rid of the 16 i would subtract 16 on both sides, right?

Answer 4

it should tell you that x=0

Answer 5

and yes

Answer 6

okay so now i have:
\[x ^{2}+8x=0\]

Answer 7

yep and that tells you already what x = so your done