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Which is the 14th term of the sequence:......
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A.59,049 B. 19,683 C. 2187 D. 6561
The given sequence is is in GP, where r= 3 and a= 1/81 \[\huge a_{n}=ar^{n-1} \rightarrow a_{14}=\frac{1}{81} (3)^{14-1} \] \[\huge \rightarrow a_{14}=\frac{1}{81} (3)^{13} \] \[\huge \rightarrow a_{14}= 81 \times 81 \times 3=19683\] Hence option B is the correct answer... @kaileyperez11
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