Question

Each day at a manufacturing plant, a lot of 8 items are manufactured and three are known to be defective. A sample of 2 of these items is selected from the lot without replacement. What is the probability distribution for the number of defective parts? Also, describe the sample space by letting c indicate a non-defective and d indicate a defective part.

Answer 1

@Zarkon

Answer 2

@radar

Answer 3

anyone, knows this problem

Answer 4

\[P(0\ defectives)=\frac{3C0\times5C2}{8C2}=you\ can\ calculate\]
\[P(1\ defective)=\frac{3C1\times5C1}{8C2}=you\ can\ caculate\]
\[P(2\ defectives)=\frac{3C2\times5C0}{8C2}=you\ can\ calculate\]