Question

what is the slope of a line that passes through te points (9,4) and (11,-2)

Answer 1

(4+2)/(9-11) = 6/(-2) = -3

Answer 2

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 9}}\quad ,&{\color{blue}{ 4}})\quad &({\color{red}{ 11}}\quad ,&{\color{blue}{ -2}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)