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Radical problem below
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\[2\sqrt{y-5}+7=17\] Answer is y=30. Can't figure out the steps
\[2\sqrt{y-5}+7=17\] \[2\sqrt{y-5}=10\] \[\sqrt{y-5}=5\] \[(\sqrt{y-5})^2=5^2\] \[y-5=25\]
Perhaps you can finish it.
Facepalm, this is the second time tonight I forgot about the square thing to get rid of the square root. Thanks for the reminder
yw
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