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Trigonometry
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how do you find the asymptote of y=2sec(3x)
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there are many, you get an asymptote when you try and divide by 0 so \(2\sec(3x)=\frac{2}{\cos(3x)}\) so when cos(3x)=0 we will have a asymptote. so for what values of x is cos(3x) = 0?
wait i'm sorta confused..so how would you graph that
so the amp= 2 and then period=2pi/3?
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