Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x 92)?

Question

Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x  92)?

perl · Answer

looks like you are missing inequality sign

perl · Answer

P( X < 92 ) ? or P( X > 92)

anonymous · Answer

the first one

mathmale · Answer

Like the problem you posted a bit later, this problem requires that you calculate the relevant z-score.  What's the z-score formula?

perl · Answer

we can use a calculator

normalcdf ( -1E99, 92, 98,6) = 0.158655

mathmale · Answer

This assumes that juiceman1000 has an appropriate TI calculator.  Juiceman1000:  what kind do you have, and have you used this calculator in probability distribution situations such as the problem you've posted?