Question

Solve for x.

-ax + 3b > 5

x > the quantity 3 times b minus 5 all over negative a

x > the quantity 5 minus 3 times b all over negative a

x < the quantity 3 times b plus 5 all over negative a

x < the quantity negative 3 times b plus 5 all over negative a

Answer 1

Just do it step by step:
-ax > 5 - 3b
-x > (5 - 3b)/a
x < -(5 - 3b)/a, notice that > becomes < after dividing by -1
x < (-3b + 5)/ (-a)
Which one is that?