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Solve for x. -ax + 3b > 5 x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a
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@greenlegodude57 can you plz help me
You need to get x on one side.
Start by subtracting 3b to both sides
You have -ax > 5 - 3b
Now divide -a to both sides
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x < 5 - 3b/-a Be sure to switch the sign, because you divided by a negative number.
Your answer is C.
O ok i got it thank you so much greenlegodude57
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