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Mathematics 16 Online
OpenStudy (geekfromthefutur):

Solve for x. -ax + 3b > 5 x > the quantity 3 times b minus 5 all over negative a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over negative a x < the quantity negative 3 times b plus 5 all over negative a

OpenStudy (geekfromthefutur):

@greenlegodude57 can you plz help me

OpenStudy (anonymous):

You need to get x on one side.

OpenStudy (anonymous):

Start by subtracting 3b to both sides

OpenStudy (anonymous):

You have -ax > 5 - 3b

OpenStudy (anonymous):

Now divide -a to both sides

OpenStudy (anonymous):

x < 5 - 3b/-a Be sure to switch the sign, because you divided by a negative number.

OpenStudy (anonymous):

Your answer is C.

OpenStudy (geekfromthefutur):

O ok i got it thank you so much greenlegodude57

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