Question

3x+4y+6z=12

Answer 1

Solution for 3x+4y+6z=12 equation:

Simplifying
3x + 4y + 6z = 12

Solving
3x + 4y + 6z = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y' to each side of the equation.
3x + 4y + -4y + 6z = 12 + -4y

Combine like terms: 4y + -4y = 0
3x + 0 + 6z = 12 + -4y
3x + 6z = 12 + -4y

Add '-6z' to each side of the equation.
3x + 6z + -6z = 12 + -4y + -6z

Combine like terms: 6z + -6z = 0
3x + 0 = 12 + -4y + -6z
3x = 12 + -4y + -6z

Divide each side by '3'.
x = 4 + -1.333333333y + -2z

Simplifying
x = 4 + -1.333333333y + -2z

Answer 2

x = 1

Answer 3

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