Andrew solved the following inequality and his work is shown below:

−4(x + 8) + 25 ≤ −2 + 1(x − 50)
−4x − 32 + 25 ≤ −2 + 1x − 50
−4x − 7 ≤ 1x − 52
−5x ≤ −45
x ≤9

What mistake did Andrew make in solving the inequality?

He subtracted 1x from both sides when he should have added 4x.

When dividing by −5, he did not change the ≤ to ≥.

He added 7 to both sides when he should have added 52.

He did not make a mistake.

Question

Andrew solved the following inequality and his work is shown below:

−4(x + 8) + 25 ≤ −2 + 1(x − 50)
−4x − 32 + 25 ≤ −2 + 1x − 50
−4x − 7 ≤ 1x − 52
−5x ≤ −45
x ≤9

What mistake did Andrew make in solving the inequality?

He subtracted 1x from both sides when he should have added 4x.

When dividing by −5, he did not change the ≤ to ≥.

He added 7 to both sides when he should have added 52.

He did not make a mistake.

anonymous · Answer

So confused on this type of math!!! needing help! Thank you!

anonymous · Answer

The answer is B.

anonymous · Answer

Remember, when you divide by a negative number you ALWAYS switch the symbol.

anonymous · Answer

how?

anonymous · Answer

When Andrew was doing step 4, he divided -5, but he didn't change the sign.

The solution should've been x ≥ 9 instead of x ≤ 9.

anonymous · Answer

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