Question

Please Help!!!
write the equation in standard form
y=3(x-4)^2-8

Answer 1

1+1= you suck

Answer 2

standard
y=ax^2
after shifting to some point(x1,y1)
(y-y1)=a(x-x1)^2 will be standard form
so move 8 on y side
y+8=3(x-4)^2

Answer 3

\[3(x ^{2}-8x+16)-8\]\[3x ^{2}-24x+48-8\]\[3x ^{2}-24x+40\]\[y=3x ^{2}-24x+40\]