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h(x)= f(g(x^3)) what does h ' (x)=?
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apply chain rule h'(x) = f'(g(x^3))*g'(x^3) *3x^2
im sorry i really dont understand how to proceed with this.
thats it, its done :) chain rule is you multiply the outside derivative by the inside derivative, in this case there were 2 nested "inside functions"
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