Question

heeeellppp.!!!!!!!!! il give medal.!!!... suppose a new car that costs $25000 depreciates by 12% each year. in about how many years will the car be worth $15000? use the equation 15,000=(25000)(0.89)^x and round the value of x to the nearest year?

Answer 1

?

Answer 2

Hello :)
I saw you asking for help in the chat, but I'm not very good at these sorts of problems... :/
I'll do what I can for you though :)

15000=(25000)(0.89)^x divide both sides by 25000

so 0.89^x = 0.6
erm then x ln(0.89) = ln(0.6)

so \[x =\frac{ \ln(0.6) }{ \ln(0.89) }\]which you would plug into your calculator :)

Answer 3

would it be 6? or how do you put it in the calculator and thank you so much.!!!

Answer 4

http://www.wolframalpha.com/input/?i=ln%280.6%29+%2F+ln%280.89%29

Answer 5

so 4?

Answer 6

yes :)

Answer 7

thank you .!!

Answer 8

you're welcome :)