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Change these polar equations to rectangular form θ = 135°
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\[\Large\bf\sf \arctan\left(\frac{y}{x}\right)\quad=\quad \theta\qquad\implies\qquad \tan 135^o\quad=\quad \frac{y}{x}\] \[\Large\bf\sf y=(\tan 135^o) x\]
Hmm that's kind of confusing to do it that way ^ lemme draw a graph instead.
So your good at these? i have one more
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