Question

Solve the system, using substitution.
3a - b = 11 and 2a + 3b = 0
A. (3, 2)
B. (3, -2)
C. (-3, 2)
D. (-3, -2)
E. no solution

Answer 1

b=3a-11
2a+3(3a-11)=0
2a+9a-33=0
11a=33
a=3
2(3)+3b=0
6+3b=0
b=2
A is your answer

Answer 2

b = 3a - 11
2a + 3(3a - 11) = 0
2a + 9a - 33 = 0
11a - 33 = 0
11a = 33
a = 3
2(3) + 3b = 0
6 + 3b = 0
3b = -6
b = -2

answer is (3,-2)....answer is B

Answer 3

You're right. Thanks for pointing that out. I'm going too fast x.x

Answer 4

lol....no problem...if I had $1 for every mistake I made, I would be rich