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OpenStudy (anonymous):
a little help with a 1st derivative test problem with trig would make my day (:
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OpenStudy (anonymous):
OpenStudy (anonymous):
did you give me the warning?
OpenStudy (phi):
I think x is 0 to pi, so the interval can't go to infinity
OpenStudy (anonymous):
like this
[pi/6,pi) ?
OpenStudy (anonymous):
its not correct
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OpenStudy (anonymous):
for part b there needs to be one more endpoint :P
OpenStudy (phi):
I assume you found the first derivative, to look for critical points (turning points) ?
and then set to 0
you should get
8 - 16 cos(2x) =0
OpenStudy (anonymous):
i got that
OpenStudy (phi):
if you simplify that you get
cos(2x)= 0.5
if x goes between 0 and pi, 2x goes from 0 to 2pi
so 2x= 60º or 2x= 300º (but in radians)
OpenStudy (phi):
so one critical point is at 2x=60 --> x=30º, which is pi/6 radians
the other is at 300/2= 150º, which is 5pi/6 radians
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OpenStudy (anonymous):
ok i got [pi/6,5pi/6] for the first one and [0,pi/6]U[5pi/6,pi] for the last.. thanks!
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