what is the probability that at least 2 will survive if expectancy for 3 people are 0.1,0.2,0.3
1st we need to clear up what those probabilities represent. You said "expectancy".Are those their probabilities of dying or living?
living
PR(AdiesBlivesClives) + Pr(AlivesBdiesClives) + Pr(AlivesBlivesCdies + Pr(all live) 0.9*0.2*0.3 + 0.1*0.8*0.3 + 0.1*0.2*0.7 + 0.1*0.2*0.3
For each person, the probability they die is 1 - Pr(live) 1-0.1=0.9 1-0.2=0.8 1-0.3=0.7
okay so we use the compliment correct?
Yes...for the probability of dying.
i got 0.098 for the total. is that the answer or do i have to do something else?
That's what I get, too
These people must have some terrible disease to have such small chances of living!
i know right haha these are just the numbers my teacher gave me
so how would i find the probability that only 2 will survive
Same way...just leave off that last 0.1*0.2*0.3...which was the prob that all 3 live.
alright thank you!
No problem.
A little secret. I actually used to work for a life insurance where we actually had to consider the probabilities of people dying when setting life insurance rates. So these types of questions are VERY familiar to me
did you get 0.092?
oh really?! hopefully you werent getting numbers like these were you?
oops! yes you are correct.
oh alright i just rechecked it all i was confused haha
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