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I got for Ay=26.67 kN, Cy=-6.67kN and Cx=-30kN.
Are you talking about the forces or the torques?
The forces.
show your work please
For Ma: -20(6)+(10x8)+(20x4)+Cy(6)=0 So for Cy=-6.67 kN. For Fy: Ay+(-.6.67)-20=0 So for Ay=26.67kN For Fx: -Cx-20-10=0 So for Cx=-30 kN. That's my solution.
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I don't get a thing!! I am sorry, as if you speak Chinese to me !!!
O, It's okay. I thought I had shown clear solution. But nm. Thanks.
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