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m^4+m^3+m+1 factor completely
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m^4+m^3 take m^3 common in this term
I got (m^3+1)(m+1) is that right, or can I factor it more? it seems to easy.
right
that's it
oh.. I just figured it would be more complicated. thanks guys:)
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yw
okay how about 125b^6-8a^3 ?
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