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Aly is looking for a new car. She has test-driven two cars but can only purchase one. The probability that she will purchase car A is 0.47 and the probability that she will purchase car B is 0.35. What is the probability that she will not purchase either car A or car B? 0.12 0.41 0.82 0.18
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what is A + B ?
if we assume that she will only purchase one car, then A+B + (other) = 1
we know A and we know B ...
0.47 + 0.3 = 0.82
then: .82 +.12 ---- 1.00 so id say the probability of doing notA or notB is 1 - (A+B) = .12
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