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Mathematics 20 Online
OpenStudy (anonymous):

The length of a text messaging conversation is normally distributed with a mean of 2 minutes and a standard deviation of .5 minutes. What is the probability that a conversation lasts longer than 3 minutes? 0.043351 0.063748 0.02275 0.095424

OpenStudy (amistre64):

2 + k(.5) = 3 is what we are looking for to determine how many standard deviations (k) we are at to assess the information

OpenStudy (amistre64):

and then of course the tools available for us, calculator or table, would have to be addressed. Or the empirical rule is a close enough approximation

OpenStudy (anonymous):

@ganeshie8

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