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A machinist creates a washer by drilling a hole through the center of a circular piece of metal. If the piece of metal has a radius of x+8 and the hole has a radius of x+2, what is the area of the washer? Use the formula A=Pie r^2 to find the area of the circle. PLEASE help I'll give a metal to whoever gives me the correct answer first c:
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|dw:1394720828069:dw|
subtracting* the radius - radius hole
radius washer (r) = radius - radius hole, r = (x+8) - (x+2) then plug the value of (r) in the equation : \[A = \pi *r ^{2}\]
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