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Evaluate each expression if x = 14, y = 5, and z = 6. (18-x)+6yz ---- 2 a.94 b.-86 c.364 d.12.5
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Is this your equation? \[18-x + \frac{ 6yz }{ 2 }\]
yes 6yz is over 2 its a fraction
\[18-x+\frac{ 6yz }{ 2 }\] \[18-14+\frac{ 6(5)(6) }{ 2 }\] \[4+\frac{ 30(6) }{ 2 }\] \[4+\frac{ 180 }{ 2 }\] Can you take it from here? Just divide 180 / 2 then add 4 to your answer.
yes thank you
94??
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Yes
thank you so much
\[4+\frac{ 180 }{ 2 }\] \[4+90\] \[94\]
No problem.
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