Question

if an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=-16t^2+vt+s where h is in feet. If the obct is propelled from a height of 12 feet with an initial velocity of 64 feet per second, its height h is given by the equation h=-16t^2+64+12

Answer 1

So you want to know the time when the object is at 72 feet correct?

Answer 2

The correct equation
h = -16t^2 + 64t + 12