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OpenStudy (anonymous):
What is the eccentricity of the ellipse given by the equation x^2/144+ y^2/64 = 1?
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OpenStudy (anonymous):
Excentricity = c/a c = √(144 - 64) = √80 ≈ 9 a² = 144 ==> a = 12 c/a ≈ 9/12 ≈ 0.75
OpenStudy (anonymous):
Thank you so much!
OpenStudy (anonymous):
welcome
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