Question

How to find Axis of Symmetry and Vertex for:

y=-6x^2-36x+7

AND

y=3x^2+2x-5

Please Help :(

Answer 1

In a quadratic with equation \(y=ax^2+bx+c\), the x-coordinate of the vertex is \(\frac{-b}{2a}\). This is also the axis of symmetry. Then, plug this x-value into the equation and you will find the y-value of the vertex. \

Answer 2

Thank you so much!! I didn't quite understand this at all but that makes it soooo much easier :D

Answer 3

you're welcome!
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