Question

What is the equation for a circle with radius = 9, and center located at ( -8, 12)?

Answer 1

The standard equation of the CIRCLE is: \[(x-x1)^2 + (y-y1)^2 = r^2\]
Where \(r\) is the radius of the circle and,
\((x_1,y_1)\) is the centre of the circle.

Just plug in the values here and you'll get the equation of the circle in \(x ~~and~~y\)

Understood? :)

Answer 2

yes thank you

Answer 3

:)