Question

PLEASE HELP!!!! PLEASE HELP!!

Answer 1

do u have to solve this equation?

Answer 2

\[\large \frac{x}{x-2}+\frac{3}{x-4}=1 \]
\[\large \frac{x(x-4)+3(x-2)}{(x-2)(x-4)}=1 \]
\[\large \frac{x^2-4x+3x-6}{(x-2)(x-4)}=1 \]
\[\large x^2-x-6=(x-2)(x-4)=x^2-6x+8 \]
(if and only if \(x\neq2\) and \(x\neq4\))
\[\large -x-6=-6x+8 \]
\[\large 5x=14 \]
\[\large x=14/5 \]